er det noen som kan løse denne oppgaven?
lg ( a^-5/9a^3) + 3 lg (3a)
Her skal man altså forenkle uttrykket
LOG
Moderatorer: Aleks855, Gustav, Nebuchadnezzar, Janhaa, DennisChristensen, Emilga
For å løse denne oppgaven må du bruke sammenhengene
lg (ab) = lg a + lg b
lg (a[sup]b[/sup]) = b lg a
1/(a[sup]b[/sup]) = a[sup]-b[/sup]
a[sup]-5[/sup] / a[sup]3[/sup] = a[sup]-8[/sup]
1/9 = 1/(3[sup]2[/sup]) = 3[sup]-2[/sup]
lg [a[sup]-5[/sup] / (9a[sup]3[/sup])] = lg a[sup]-8[/sup] + lg (1/9) = -8 lg a -2 lg 3
3 lg (3a) = 3 lg 3 + 3 lg a
lg [a[sup]-5[/sup] / (9a[sup]3[/sup])] + 3 lg (3a)
= -8 lg a -2 lg 3 + 3 lg 3 + 3 lg a
= lg 3 - 5 lg a
lg (ab) = lg a + lg b
lg (a[sup]b[/sup]) = b lg a
1/(a[sup]b[/sup]) = a[sup]-b[/sup]
a[sup]-5[/sup] / a[sup]3[/sup] = a[sup]-8[/sup]
1/9 = 1/(3[sup]2[/sup]) = 3[sup]-2[/sup]
lg [a[sup]-5[/sup] / (9a[sup]3[/sup])] = lg a[sup]-8[/sup] + lg (1/9) = -8 lg a -2 lg 3
3 lg (3a) = 3 lg 3 + 3 lg a
lg [a[sup]-5[/sup] / (9a[sup]3[/sup])] + 3 lg (3a)
= -8 lg a -2 lg 3 + 3 lg 3 + 3 lg a
= lg 3 - 5 lg a