Hvis [tex]\,\,f(x)=\frac{x}{x-1}[/tex],
bestem så:
[tex](fofof...of)_{9\,\text ganger}[/tex]
der
[tex]fof = f(f(x))[/tex]
vgs kos 2
Moderatorer: Vektormannen, espen180, Aleks855, Solar Plexsus, Gustav, Nebuchadnezzar, Janhaa
[tex]fof=f(f(x))=\frac{\frac{x}{x-1}}{\frac{x}{x-1}-1}=\frac{\frac{x}{x-1}}{\frac{x}{x-1}-\frac{x+1}{x-1}}=\frac{\frac{x}{x-1}}{\frac{x-x+1}{x-1}}=\frac{x}{x-1}*\frac{x-1}{1}=\frac{x}{1}=x[/tex]
[tex]fofof=f(f(f(x)))=\frac{x}{x-1}[/tex]
[tex]fofofof=f(f(f(f)))=\frac{\frac{x}{x-1}}{\frac{1}{x-1}}=\frac{x}{x-1}*\frac{x-1}{1}=\frac{x}{1}=x[/tex]
Ser et mønster..
[tex]fofofofof=\frac{x}{x-1}[/tex]
[tex]fofofofofofofofof=f(x)=\frac{x}{x-1}[/tex]
[tex]fofof=f(f(f(x)))=\frac{x}{x-1}[/tex]
[tex]fofofof=f(f(f(f)))=\frac{\frac{x}{x-1}}{\frac{1}{x-1}}=\frac{x}{x-1}*\frac{x-1}{1}=\frac{x}{1}=x[/tex]
Ser et mønster..
[tex]fofofofof=\frac{x}{x-1}[/tex]
[tex]fofofofofofofofof=f(x)=\frac{x}{x-1}[/tex]
[tex]i*i=-1[/tex]
Omnia mirari etiam tritissima - Carl von Linné
( Find wonder in all things, even the most commonplace.)
Det er åpning og lukking av ionekanaler i nerveceller som gjør det mulig for deg å lese dette.
Omnia mirari etiam tritissima - Carl von Linné
( Find wonder in all things, even the most commonplace.)
Det er åpning og lukking av ionekanaler i nerveceller som gjør det mulig for deg å lese dette.
Bra, stemmer.Drezky skrev:[tex]fof=f(f(x))=\frac{\frac{x}{x-1}}{\frac{x}{x-1}-1}=\frac{\frac{x}{x-1}}{\frac{x}{x-1}-\frac{x+1}{x-1}}=\frac{\frac{x}{x-1}}{\frac{x-x+1}{x-1}}=\frac{x}{x-1}*\frac{x-1}{1}=\frac{x}{1}=x[/tex]
[tex]fofof=f(f(f(x)))=\frac{x}{x-1}[/tex]
[tex]fofofof=f(f(f(f)))=\frac{\frac{x}{x-1}}{\frac{1}{x-1}}=\frac{x}{x-1}*\frac{x-1}{1}=\frac{x}{1}=x[/tex]
Ser et mønster..
[tex]fofofofof=\frac{x}{x-1}[/tex]
[tex]fofofofofofofofof=f(x)=\frac{x}{x-1}[/tex]
La verken mennesker eller hendelser ta livsmotet fra deg.
Marie Curie, kjemiker og fysiker.
[tex]\large\dot \rho = -\frac{i}{\hbar}[H,\rho][/tex]
Marie Curie, kjemiker og fysiker.
[tex]\large\dot \rho = -\frac{i}{\hbar}[H,\rho][/tex]