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Janhaa wrote:[tex]\frac{\frac{x^2}{3}+\frac{5x}{6}}{\frac{x}{12}}[/tex] [tex]=(\frac{x^2}{3})*({\frac{12}{x}})+(\frac{5x}{6})*({\frac{12}{x})[/tex] [tex]=4x+10[/tex]