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(2x-1) i andre + 1 = 3 - (4x-3) (2-x)

(2x-1)[sup]2[/sup] + 1 = 3 - (4x-3)(2-x)
(2x-1)(2x-1) + 1 = 3 - (8x-4x²-6+3x)
4x²-2x-2x+1+1=3-8x+4x²+6-3x
-4x+2=9-11x
7x = 7

x = 1

(2x-1) i andre + 1 = 3 - (4x-3) (2-x)
(2x-1)(1x-1)+1=3-(4x-3)(2-x)
(2x[sup]2[/sup]-2x-1x+1)=3-(8x-4x[sup]2[/sup]-6+3x)
2x[sup]2[/sup]-2x-1x+1=3-8x+4x[sup]2[/sup]+6-3x
2x[sup]2[/sup]-2x-1x+8x-4x[sup]2[/sup]+3x=3+6-1
-2x[sup]2[/sup]+1x=8