2^5x / 2^2x - 40 = 0
Hvordan løser man den?
så langt har jeg kommet:
5xlog2 / 2xlog2 = 40
Kommer ikke lenger enn dette.
lgx
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[tex] \frac{{{2^{5x}}}}{{{2^{2x}}}} - 40 = 0 [/tex]
[tex]\lg \left( {\frac{{{2^{5x}}}}{{{2^{2x}}}}} \right) = \lg \left( {40} \right)[/tex]
[tex] \lg \left( {{2^{5x}}} \right) - \lg \left( {{2^{2x}}} \right) = \lg \left( {40} \right) [/tex]
[tex] \frac{{{2^{5x}}}}{{{2^{2x}}}} - 40 = 0 [/tex]
[tex]\lg \left( {\frac{{{2^{5x}}}}{{{2^{2x}}}}} \right) = \lg \left( {40} \right)[/tex]
[tex] \lg \left( {{2^{5x}}} \right) - \lg \left( {{2^{2x}}} \right) = \lg \left( {40} \right) [/tex]