[tex]\frac{2}{\sqrt[4]{2^3}} = [/tex]
[tex]2 \times \frac{1}{2^{\frac{3}{4}}} = [/tex]
[tex]2^1 \times 2^{-\frac{3}{4}} = [/tex]
[tex]2^{1-\frac{3}{4}} = [/tex]
[tex]2^{\frac{1}{4}} = [/tex]
[tex]\sqrt[4]{2}[/tex]
Potenser
Moderatorer: Aleks855, Gustav, Nebuchadnezzar, Janhaa, DennisChristensen, Emilga
sEirik skrev:[tex]\frac{2}{\sqrt[4]{2^3}} = [/tex]
[tex]2 \times \frac{1}{2^{\frac{3}{4}}} = [/tex]
[tex]2^1 \times 2^{-\frac{3}{4}} = [/tex]
[tex]2^{1-\frac{3}{4}} = [/tex]
[tex]2^{\frac{1}{4}} = [/tex]
[tex]\sqrt[4]{2}[/tex]
Aha, nå forstår jeg, tusen hjertelig
8^1/3 * 2^2/3
det blir
[tex]\frac{8^1}{3} \cdot \frac{2^2}{3} =[/tex]
[tex]\frac{8 \cdot 4}{3 \cdot 3} =[/tex]
[tex]\frac{32}{9}[/tex]
Du mente sikkert det her ...
[tex]8^{\frac{1}{3}} \cdot 2^{\frac{2}{3}}[/tex]
... og da må du HUSKE PARANTESER!
[tex]8^{\frac{1}{3}} \cdot 2^{\frac{2}{3}} =[/tex]
Vi vet at [tex]8 = 2^3[/tex], så vi setter inn:
[tex](2^3)^{\frac{1}{3}} \cdot 2^{\frac{2}{3}} =[/tex]
[tex]2^{3 \cdot \frac{1}{3} + \frac {2}{3}} =[/tex]
[tex]2^{\frac{5}{3}} =[/tex]
[tex]\sqrt[3]{2^5} =[/tex]
det blir
[tex]\frac{8^1}{3} \cdot \frac{2^2}{3} =[/tex]
[tex]\frac{8 \cdot 4}{3 \cdot 3} =[/tex]
[tex]\frac{32}{9}[/tex]
Du mente sikkert det her ...
[tex]8^{\frac{1}{3}} \cdot 2^{\frac{2}{3}}[/tex]
... og da må du HUSKE PARANTESER!
[tex]8^{\frac{1}{3}} \cdot 2^{\frac{2}{3}} =[/tex]
Vi vet at [tex]8 = 2^3[/tex], så vi setter inn:
[tex](2^3)^{\frac{1}{3}} \cdot 2^{\frac{2}{3}} =[/tex]
[tex]2^{3 \cdot \frac{1}{3} + \frac {2}{3}} =[/tex]
[tex]2^{\frac{5}{3}} =[/tex]
[tex]\sqrt[3]{2^5} =[/tex]