oppgave 5.
a)
[tex]f(40,10) = -40^2-1.5 \cdot 40 \cdot 10 - 10^2 +150 \cdot 40 + 130 \cdot 10 -500[/tex]
[tex]f(40,10)=6000[/tex]
b)
[tex]f(20,y) = -20^2-1.5 \cdot 20 y - y^2 +150 \cdot 20 +130y -500 = 4500[/tex]
[tex]2100 - 30y - y^2 + 130 y = 4500[/tex]
[tex]y^2 -100y +2400= 0[/tex]
[tex]y= \frac{100 \pm \sqrt{(-100)^2 - 4 \cdot 1 \cdot 2400}}{2 \cdot 1}[/tex]
[tex]y = 50 \pm 10[/tex]
[tex]y =60 \ \vee y=40[/tex]
bleh... du kom meg i forkjøpet zell, så da avslutter jeg her
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