Løs ligningene:
1) e^(x^3) = 15
2) 4^x - (10 * 2^x) - 24 = 0
3) |x - 2| = x
Tusen takk for svar!
Ligninger (med e^x, eksponential og absoluttverdi)
Moderatorer: Aleks855, Gustav, Nebuchadnezzar, Janhaa, DennisChristensen, Emilga
[tex]e^{x^3} = 15[/tex]
[tex]\ln(e^{x^3}) = \ln(15)[/tex]
[tex]x^3 = \ln15[/tex]
[tex]x = \sqr[3]{\ln15}[/tex]
[tex]\ln(e^{x^3}) = \ln(15)[/tex]
[tex]x^3 = \ln15[/tex]
[tex]x = \sqr[3]{\ln15}[/tex]
The square root of Chuck Norris is pain. Do not try to square Chuck Norris, the result is death.
http://www.youtube.com/watch?v=GzVSXEu0bqI - Tom Lehrer
http://www.youtube.com/watch?v=GzVSXEu0bqI - Tom Lehrer
[tex]4^x - (10 \cdot 2^x) - 24 = 0 [/tex]
[tex](2^x)^2-10\cdot2^x-24=0[/tex]
[tex]u=2^x[/tex]
[tex]u^2-10u-24=0[/tex]
andregradsformelen:
[tex]u_1=12[/tex]
[tex]u_2=-2[/tex]
[tex]2^x \not = -2[/tex]
[tex]2^x=12[/tex]
[tex]x=\frac{\ln{12}}{\ln{2}}[/tex]
[tex](2^x)^2-10\cdot2^x-24=0[/tex]
[tex]u=2^x[/tex]
[tex]u^2-10u-24=0[/tex]
andregradsformelen:
[tex]u_1=12[/tex]
[tex]u_2=-2[/tex]
[tex]2^x \not = -2[/tex]
[tex]2^x=12[/tex]
[tex]x=\frac{\ln{12}}{\ln{2}}[/tex]
Sist redigert av Charlatan den 10/08-2007 16:27, redigert 1 gang totalt.
mycket enig med Jarle12
[tex](a^p)^q = a^{p\cdot q}[/tex]
[tex](a^p)^q = a^{p\cdot q}[/tex]
The square root of Chuck Norris is pain. Do not try to square Chuck Norris, the result is death.
http://www.youtube.com/watch?v=GzVSXEu0bqI - Tom Lehrer
http://www.youtube.com/watch?v=GzVSXEu0bqI - Tom Lehrer