trenger litt hjelp med denne
på forhånd takk
løs denne:
ln(1-x)- lnx = 0
logaritmer
Moderatorer: Aleks855, Gustav, Nebuchadnezzar, Janhaa, DennisChristensen, Emilga
lnx=log[sub]e[/sub]x
ln(1-x)-lnx=0
log[sub]e[/sub](1-x) - log[sub]e[/sub]x=0
log[sub]e[/sub][(1-x)/x]=0
(1-x)/x=e[sup]0[/sup]
(1-x)/x=1
1-x=x
2x=1
x=0,5
litt ekstra
log[sub]a[/sub]x +log[sub]a[/sub]y=log (x*y)
log[sub]a[/sub]x - log[sub]a[/sub]y=log (x/y)
![Wink :wink:](./images/smilies/icon_wink.gif)
ln(1-x)-lnx=0
log[sub]e[/sub](1-x) - log[sub]e[/sub]x=0
log[sub]e[/sub][(1-x)/x]=0
(1-x)/x=e[sup]0[/sup]
(1-x)/x=1
1-x=x
2x=1
x=0,5
litt ekstra
![Exclamation :!:](./images/smilies/icon_exclaim.gif)
log[sub]a[/sub]x +log[sub]a[/sub]y=log (x*y)
log[sub]a[/sub]x - log[sub]a[/sub]y=log (x/y)
![Wink :wink:](./images/smilies/icon_wink.gif)