diff. likning
Lagt inn: 06/11-2007 23:20
[tex]y^\prime\ = e^{x+y}[/tex] når y(0) = 0
[tex]\frac{dy}{dx} = e^{x+y}[/tex]
[tex]ln \frac{dy}{dx} = lne^{x+y}[/tex]
[tex]ln dy - lndx = x+y[/tex]
[tex]ln dy -y = ln dx + x[/tex]
[tex]dy - e^y = dx + e^x[/tex]
[tex]\int dy - e^y = \int dx +e^x[/tex]
[tex]y - e^y = x +e^x + C[/tex]
hva skjer her egentlig? =(
[tex]\frac{dy}{dx} = e^{x+y}[/tex]
[tex]ln \frac{dy}{dx} = lne^{x+y}[/tex]
[tex]ln dy - lndx = x+y[/tex]
[tex]ln dy -y = ln dx + x[/tex]
[tex]dy - e^y = dx + e^x[/tex]
[tex]\int dy - e^y = \int dx +e^x[/tex]
[tex]y - e^y = x +e^x + C[/tex]
hva skjer her egentlig? =(