Hvilke steg gjøres for å forkorte denne:
[tex]z = \frac{2}{5}(x+1)^{\frac{5}{2}} - \frac{2}{3}(x+1)^{\frac{3}{2}} + C[/tex]
til denne?:
[tex]z = \frac{2}{15}(x+1)^{\frac{3}{2}}(3x-2) + C[/tex]
Ser ikke helt hvordan...
iBrus
Forkorte...
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Fibonacci92
- Abel
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Hint: $(x+1)^{\frac{5}{2}} = (x+1)^{\frac{3}{2}}\cdot (x+1)$
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DennisChristensen
- Grothendieck
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$ z = \frac{2}{5}(x+1)^{\frac{5}{2}} - \frac{2}{3}(x+1)^{\frac{3}{2}} + C \\iBrus skrev:Hvilke steg gjøres for å forkorte denne:
[tex]z = \frac{2}{5}(x+1)^{\frac{5}{2}} - \frac{2}{3}(x+1)^{\frac{3}{2}} + C[/tex]
til denne?:
[tex]z = \frac{2}{15}(x+1)^{\frac{3}{2}}(3x-2) + C[/tex]
Ser ikke helt hvordan...
iBrus
= (x+1)^{\frac{3}{2}}\left(\frac{2}{5}(x+1) - \frac{2}{3}\right) + C \\
= (x+1)^{\frac{3}{2}}\left(\frac{6}{15}(x+1) - \frac{10}{15}\right) + C \\
= \frac{2}{15}(x+1)^{\frac{3}{2}}\left(3(x+1) - 5\right) + C \\
=\frac{2}{15}(x+1)^{\frac{3}{2}}(3x-2) + C$