Sommerintegraler
Lagt inn: 24/06-2007 05:30
Jeg har klart å få tak i en indisk lærebok fra vgs, og har funnet et par interessante integraler derfra som vi kan bryne oss på.
Jeg erstatter løste integraler.
[tex]I_1 = \int \sqrt{\frac{5-x}{x-2}} \rm{d} x \qquad \rm{Janhaa} \\ \color{red} I_2 = \int (x+2)\sqrt{2x^2+2x+1} \rm{d} x \qquad \rm{daofeishi}\\ I_3 = \int \frac{\rm{d}x}{x + \sqrt{1-x^2}} \qquad \rm{Janhaa} \\ I_4 = \int \sqrt{\sqrt{x+2\sqrt{2x-4}}+\sqrt{x-2\sqrt{2x-4}}} \rm{d}x \qquad \rm{daofeishi} \\ I_5 = \int \frac{x^2-8}{x^4+7x^2+64} \rm{d} x \qquad \rm{Janhaa} \\ I_6 = \int \frac{x^2-3x+1}{\sqrt{1-x^2}} \rm{d}x \qquad \rm{Janhaa} \\ I_7 = \int \frac{\cos x}{\left( \cos \frac{x}{2} + \sin \frac{x}{2} \right)^3} \rm{d}x \qquad \rm{Janhaa} \\ I_8 = \int \tan(3x) \tan(2x)\tan(x) \rm{d}x \qquad \rm{mrcreosote} \color{black} \\ I_9 = \int \ln \ln x + (\ln x)^{-2} \rm{d} x \qquad \rm{Janhaa}[/tex]
[tex]\color{red}I_{10} = \int e^{\frac{x}{2}}\left( \frac{2-\sin x}{1- \cos x} \right) \rm{d}x [/tex]
[tex]\color{black} I_{11}= \int \frac{\rm{d}x}{2+\cos(x)} \qquad \rm{Janhaa}[/tex]
[tex]\color{red} I_{12} = \int \frac{x \rm{d}x}{\sqrt{1+\sin(x)}} \\ I_{13} = \int \frac{\rm{d}x}{(x^2+1)\sqrt{x}}[/tex]
Jeg erstatter løste integraler.
[tex]I_1 = \int \sqrt{\frac{5-x}{x-2}} \rm{d} x \qquad \rm{Janhaa} \\ \color{red} I_2 = \int (x+2)\sqrt{2x^2+2x+1} \rm{d} x \qquad \rm{daofeishi}\\ I_3 = \int \frac{\rm{d}x}{x + \sqrt{1-x^2}} \qquad \rm{Janhaa} \\ I_4 = \int \sqrt{\sqrt{x+2\sqrt{2x-4}}+\sqrt{x-2\sqrt{2x-4}}} \rm{d}x \qquad \rm{daofeishi} \\ I_5 = \int \frac{x^2-8}{x^4+7x^2+64} \rm{d} x \qquad \rm{Janhaa} \\ I_6 = \int \frac{x^2-3x+1}{\sqrt{1-x^2}} \rm{d}x \qquad \rm{Janhaa} \\ I_7 = \int \frac{\cos x}{\left( \cos \frac{x}{2} + \sin \frac{x}{2} \right)^3} \rm{d}x \qquad \rm{Janhaa} \\ I_8 = \int \tan(3x) \tan(2x)\tan(x) \rm{d}x \qquad \rm{mrcreosote} \color{black} \\ I_9 = \int \ln \ln x + (\ln x)^{-2} \rm{d} x \qquad \rm{Janhaa}[/tex]
[tex]\color{red}I_{10} = \int e^{\frac{x}{2}}\left( \frac{2-\sin x}{1- \cos x} \right) \rm{d}x [/tex]
[tex]\color{black} I_{11}= \int \frac{\rm{d}x}{2+\cos(x)} \qquad \rm{Janhaa}[/tex]
[tex]\color{red} I_{12} = \int \frac{x \rm{d}x}{\sqrt{1+\sin(x)}} \\ I_{13} = \int \frac{\rm{d}x}{(x^2+1)\sqrt{x}}[/tex]