anta [tex]a_0,a_1,......,a_{2018}[/tex] er heltall slik at [tex](x^2-3x+1)^{1009}=\sum_{0}^{2018}a_kx^k[/tex]
for alle reelle tall x. Finn resten når [tex]a_0^2+a_1^2+...a_{2018}^2[/tex] blir dividert med [tex]2017^{21}[/tex]
olympiad problem
Moderatorer: Vektormannen, espen180, Aleks855, Solar Plexsus, Gustav, Nebuchadnezzar, Janhaa