A =
[symbol:integral] 9/2dx - [symbol:integral] (4+x^2-(1/2)x^4)dx
Integral går fra -1 til 1
9/2x - 4x+(1/3)^x3-(0,1)x^5
Får da 9/2 + 9/2 = 9 og 4*1 + 1/3-0.1 + 4-0.33+0.1 = 8
Får da 9-8= 1 men det er feil. svaret er 8/15 =0,53
Integral Bestem verden A der
Moderators: Vektormannen, espen180, Aleks855, Solar Plexsus, Gustav, Nebuchadnezzar, Janhaa
[tex]\frac{9}{2}x-4x-\frac{1}{3}x^3+\frac{1}{10}x^5[/tex]
grenser fra -1 til 1:
[tex]\frac{9}{2}-4-\frac{1}{3}+\frac{1}{10}-(\frac{9}{2}(-1)-4(-1)-\frac{1}{3}(-1)^3+\frac{1}{10}(-1)^5)[/tex]
[tex]\frac{9}{2}-4-\frac{1}{3}+\frac{1}{10}-(-\frac{9}{2}+4+\frac{1}{3}-\frac{1}{10})[/tex]
[tex]\frac{9}{2}-4-\frac{1}{3}+\frac{1}{10}+\frac{9}{2}-4-\frac{1}{3}+\frac{1}{10}=0,53[/tex]
grenser fra -1 til 1:
[tex]\frac{9}{2}-4-\frac{1}{3}+\frac{1}{10}-(\frac{9}{2}(-1)-4(-1)-\frac{1}{3}(-1)^3+\frac{1}{10}(-1)^5)[/tex]
[tex]\frac{9}{2}-4-\frac{1}{3}+\frac{1}{10}-(-\frac{9}{2}+4+\frac{1}{3}-\frac{1}{10})[/tex]
[tex]\frac{9}{2}-4-\frac{1}{3}+\frac{1}{10}+\frac{9}{2}-4-\frac{1}{3}+\frac{1}{10}=0,53[/tex]
ærbødigst Gill