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Re: Ulikhetmaraton

Posted: 06/06-2025 01:15
by lfe
Ny ulikhet:
La $a,b,c,d$ være positive reelle tall slik at $abcd=\frac{1}{4}$. Vis følgende ulikhet og finn likhetstilfelle(ne):
\[
\left ( 16ac+\frac{a}{c^2d}+\frac{16c}{a^2d}+\frac{4}{ac}\right ) \left ( bd +\frac{b}{256d^2c}+\frac{d}{b^2a}+\frac{1}{64bd}\right ) \geq \frac{81}{4}
\]