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[symbol:integral] (1-x)[sup]2[/sup] e[sup]-x[/sup] x[1,0]
fasit:1-(2/e)

russ07 wrote:[symbol:integral] (1-x)[sup]2[/sup] e[sup]-x[/sup] x[1,0]
fasit:1-(2/e)

[tex]I=\int_0^1 (1-x)^2e^{-x}dx[/tex]

bruk delvis integrasjon:

[tex]I=\int_0^1 (1-x)^2e^{-x}dx=[/tex][tex]-e^{-x}(x^2+1)|_0^1[/tex]

[tex]I=-e^{-1}\cdot (1+1)+1=1-{2\over e}[/tex]

Janhaa wrote:

russ07 wrote:[symbol:integral] (1-x)[sup]2[/sup] e[sup]-x[/sup] x[1,0]
fasit:1-(2/e)

[tex]I=\int_0^1 (1-x)^2e^{-x}dx[/tex]

bruk delvis integrasjon:

[tex]I=\int_0^1 (1-x)^2e^{-x}dx=[/tex][tex]-e^{-x}(x^2+1)|_0^1[/tex]

[tex]I=-e^{-1}\cdot (1+1)+1=1-{2\over e}[/tex]

skal det ikke være dobbel intgrasjon her..eller???

jau

TurboN wrote:jau

aha, så du har gjort dobbel intgrasjon her
takk for hjelpen...God natt