matematikk.net

hei hvordan gjør jeg:

[symbol:integral] xe^3x dx

merci

[tex]u = x \qquad u^\prime = 1[/tex]

[tex]v^\prime = e^{3x} \qquad v = \frac 13 e^{3x}[/tex]

[tex]\int x e^{3x} dx = x \cdot \frac 13 e^{3x} - \int 1 \cdot \frac 13 e^{3x} dx = \underline{\underline{\frac 13 x e^{3x} - \frac 19 e^{3x} +C}}[/tex]