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				???
				Posted: 23/03-2007 10:06
				by janneamble
				elipsen er gitt ved r(t)= (4cosT,2sinT)
vis at elipsen har likningen
x^2/4^2  +  y^2/2^2 = 1
			 
			
					
				
				Posted: 23/03-2007 10:26
				by Janhaa
				[tex]\vec r=[4\cos(T),\,2\sin(T)][/tex]
x = 4cos(T)  og  y = 2sin(T)
[tex]{x^2\over 4^2}\,+\,{y^2\over 2^2}\,=\,{4^2\cos^2(T)\over 4^2}\,+\,{4\sin^^2(T)\over 4}\,=\,{cos^2(T)\,+\,sin^2(T)}\,=\,1[/tex]
): [tex]\;{x^2\over 4^2}\,+\,{y^2\over 2^2}\,=\,1[/tex]