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trigonometrisk integrasjon
Posted: 04/04-2005 23:10
by Bare innom
Hjelp
[itgl][/itgl] sinx dx=
Posted: 04/04-2005 23:15
by Kent
Prøv
-cos(x)+C
(formelsamling)
Posted: 05/04-2005 11:55
by bareinnom
Sorry, det ble littfeil
Oppgaven skulle være:
sin2x dx (altså sinus i andre)
Posted: 05/04-2005 12:57
by zinln
[itgl][/itgl]sin[sup]2[/sup]xdx---->1/2 *sin[sup]2[/sup]*x[sup]2[/sup]
Posted: 05/04-2005 13:10
by Kent
[itgl][/itgl]sin[sup]2[/sup](x)dx=(x/2)-(1/4)sin(2x)+C
Litt utvidet formelsamling, hehe...
Evt. utnytt identiteten
sin[sup]2[/sup](x)=(1/2)(1-cos(2x))
[itgl][/itgl]sin[sup]2[/sup](x)dx=(1/2)[itgl][/itgl]1-cos(2x)dx=(1/2)(x-(1/2)sin(2x)
=(x/2)-(1/4)sin(2x)+C