Hva gjør jeg galer her!!! Frustrert.
Posted: 13/10-2009 16:24
x^2+y^2-2x-2y=-1
(dx^2)/dx+(dy^2)/dx-2dx/dx-2dy/dx=-1d/dx
2x+2y dy/dx-2-2dy/dx=0
dy/dx (2y-2)=2-2x
dy/dx=(2-2x)/(2y-2)
(2-2x)/(2y-2)=√3
2-2x=(2y-2)√3
x= (√3(2y)-2√3-2)/(-2)
x=-√3 y+1+√3
( -√3 y+(1+√3))^2+y^2-2(-√3 y+1+√3)-2y=-1
3y^2+(4+2√3)+y^2+2√3 y-(2+2√3)-2y+1=0
3y^2+y^2-(2-2√3 y)+3=0
4y^2+1.46..+3=0
x=(-b±√(b^2-4ac))/2a
svara skal bli x=0.1340 og y skal bli 1.5
(dx^2)/dx+(dy^2)/dx-2dx/dx-2dy/dx=-1d/dx
2x+2y dy/dx-2-2dy/dx=0
dy/dx (2y-2)=2-2x
dy/dx=(2-2x)/(2y-2)
(2-2x)/(2y-2)=√3
2-2x=(2y-2)√3
x= (√3(2y)-2√3-2)/(-2)
x=-√3 y+1+√3
( -√3 y+(1+√3))^2+y^2-2(-√3 y+1+√3)-2y=-1
3y^2+(4+2√3)+y^2+2√3 y-(2+2√3)-2y+1=0
3y^2+y^2-(2-2√3 y)+3=0
4y^2+1.46..+3=0
x=(-b±√(b^2-4ac))/2a
svara skal bli x=0.1340 og y skal bli 1.5