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Derivering
Posted: 18/05-2011 14:22
by likzu
Noen som skjønner denne?:)
Deriver disse funksjonene :
f (x) = 3x^4 + (Kvadratrot) X - 2/x^3
Posted: 18/05-2011 16:35
by krje1980
Mener du:
[tex]f(x) = 3x^{4} + \sqrt{x} - \frac{2}{x^3}[/tex]
eller:
[tex]f(x) = 3x^{4} + \sqrt{x - \frac{2}{x^{3}}[/tex]
Posted: 18/05-2011 16:57
by MatteNoob
krje1980 wrote:Mener du:
[tex]f(x) = 3x^{4} + \sqrt{x} - \frac{2}{x^3}[/tex]
eller:
[tex]f(x) = 3x^{4} + \sqrt{x - \frac{2}{x^{3}}[/tex]
[tex]f(x) = 3x^{4} + \sqrt{x} - \frac{2}{x^3}[/tex]
gir
[tex]f\prime(x) = 12x^3 + \frac{1}{2\sqrt x} + \frac{6}{x^4}[/tex]
og
[tex]f(x) = 3x^{4} + \sqrt{x - \frac{2}{x^{3}}[/tex]
gir
[tex]f\prime(x) = 12 x^3 + \frac{1}{2\sqrt{ x - \frac{2}{x^3}}} \cdot \left(1 + \frac{6}{x^4}\right)[/tex]