matematikk.net

Oppgave 9.1.22
La [tex]\: I_{n}=\int sin^{n}(x) dx \:[/tex]

c)Vis at [tex]\: I_{n}=\frac{n-1}{n}I_{n-2}-\frac{1}{n}sin^{n-1}(x)cos(x)[/tex]

sin^n(x) = sin^(n-2)(x)*sin^2(x) (evnt n-1 og 1).