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Hjelp til likning?
Posted: 27/02-2012 21:41
by Hadron
3/2x-1/6=2/3-1/2x
Posted: 27/02-2012 21:42
by Nebuchadnezzar
mener du
[tex]\frac32 x \, - \, \frac16 \, = \, \frac23 \, - \, \frac12x [/tex]
?
Posted: 27/02-2012 21:44
by Hadron
yes
Posted: 27/02-2012 22:31
by Nebuchadnezzar
Posted: 28/02-2012 18:52
by Hadron
3/2x - 1/6 =2/3 - 1/2x
9x - 6 = 4 - 3x
9x+3x = 4+6
12x =10
-----------
12 12
x=10
------
12
Posted: 28/02-2012 18:56
by Aleks855
Code: Select all
3/2x - 1/6 =2/3 - 1/2x
9x - 6 = 4 - 3x
9x+3x = 4+6
12x =10
-----------
12 12
x=10
------
12
Hvis du skal bruke mellomrom for formatering, så fungerer det bedre med CODE-tags

Posted: 28/02-2012 19:04
by Hadron
er svaret riktig?
Posted: 28/02-2012 19:13
by Aleks855
Nei, slurvefeil i andre linje. Det skal ikke være 9x-6 men...?
Ellers er utregningen fin!