logaritme likning
Posted: 23/10-2005 23:11
hvordan løser vi denne?
3*2^x=3^x
3*2^x=3^x
3*2[sup]x[/sup] = 3[sup]x[/sup]
3[sup]x[/sup]/2[sup]x[/sup] = 3
(3/2)[sup]x[/sup] = 3
ln [(3/2)[sup]x[/sup]] = ln 3
x*ln(3/2) = ln 3
x = ln 3 / ln(3/2) ≈ 2,71.