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Formelsnuing...Hjelp?
Posted: 11/09-2013 10:37
by ash1982
Kan noen hjelpe meg og snu denne formen for v^3
P=1/2*ρ*A*v^3*16/27*Ƞ
Re: Formelsnuing...Hjelp?
Posted: 11/09-2013 10:41
by Aleks855
$\displaystyle P = \frac12\cdot pAv^3\frac{16}{27}*n$ (Fant ikke TeX-koden for Ƞ)
$\displaystyle v^3 = \frac{54P}{16pAn}$