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Differenasial ligning

Posted: 09/01-2014 17:22
by Guest
hei,

hvordan løser jeg:

[tex]y^\prime (x^2-x) +y=x^2-1 \: \: \: \: \: x>1[/tex]

Takk!

Re: Differenasial ligning

Posted: 09/01-2014 17:33
by Janhaa
Gjest wrote:hei,hvordan løser jeg:
[tex]y^\prime (x^2-x) +y=x^2-1 \: \: \: \: \: x>1[/tex]Takk!
integrerende faktor:
[tex]I: F. : \int \frac{dx}{x^2-x} = \lg|\frac{1-x}{x}|[/tex]
der
[tex]\mu=exp(ln|\frac{1-x}{x}|)=\frac{1-x}{x}[/tex]

etc...