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Opprinnelige prisen...! *HJELP*
Posted: 15/12-2005 22:04
by KjElL 91
a^2*(3a^3)^2*(-2b^2)^3
-------------------------------
(6a-^2*b^4)^2
Hjelp?!
Posted: 16/12-2005 00:12
by Solar Plexsus
a[sup]2[/sup] [sub]*[/sub] (3a[sup]3[/sup])[sup]2[/sup] [sub]*[/sub] (-2b[sup]2[/sup])[sup]3[/sup]
--------------------- =
(6a[sup]2[/sup] [sub]*[/sub] b[sup]4[/sup])[sup]2[/sup]
a[sup]2[/sup] [sub]*[/sub] (9a[sup]6[/sup]) [sub]*[/sub] (-8b[sup]6[/sup])
------------------- =
36a[sup]4[/sup][sub] * [/sub]b[sup]8[/sup]
-72a[sup]8[/sup] [sub]*[/sub] b[sup]6[/sup]
----------- =
36a[sup]4[/sup] [sub]*[/sub] b[sup]8[/sup]
-2a[sup]4[/sup] [sub]*[/sub] b[sup]-2[/sup].