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Likninger

Posted: 11/04-2016 20:39
by Ruben4
[img]oppgaver/img]

Re: Likninger

Posted: 11/04-2016 20:46
by Ruben4
Trenger hjelp med disse:

a) [tex]x^{2}-4x=21[/tex]
b) [tex]200\cdot 1,023^{x}=250[/tex]
c) [tex](x^{2}-4)e^{^{x}}=0[/tex]
d) [tex]\frac{x+8}{x-6}=x[/tex]

Re: Likninger

Posted: 11/04-2016 20:54
by Kjemikern
Ruben4 wrote:Trenger hjelp med disse:

a) [tex]x^{2}-4x=21[/tex]
b) [tex]200\cdot 1,023^{x}=250[/tex]
c) [tex](x^{2}-4)e^{^{x}}=0[/tex]
d) [tex]\frac{x+8}{x-6}=x[/tex]

a)
[tex]x^2-4x=21\\x^2-4x-21=0\\(x+3)(x-7)=0\\x=7,x=-3[/tex]

b)
[tex]200\cdot 1,023^x=250\\1,023^x=1,25\\x\ln1.023=\ln1.25\\\\x=\frac{\ln1.25}{\ln1,023}[/tex]

c)
[tex](x^2-4)e^x=0\\(x-2)(x+2)e^x=0\\x=2,x=-2[/tex]

d)

[tex]\frac{x+8}{x-6}=x\\\\x+8=x^2-6x\\x^2-7x-8=0\\(x+1)(x-8)=0\\x=-1,x=8[/tex]

Re: Likninger

Posted: 11/04-2016 20:58
by Ruben4
Tusen takk :D