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sin
Posted: 16/04-2016 10:51
by stimorolextra
Hvorfor er sin(2x-pi) det samme som -sin(2x)?
Re: sin
Posted: 16/04-2016 11:07
by pit
[tex]sin(2x-\pi) = sin(2x)cos(-\pi) + sin(-\pi)cos(2x) = -sin(2x)[/tex]
Re: sin
Posted: 16/04-2016 11:08
by pit
[tex]sin(2x-\pi) = sin(2x)cos(-\pi) - sin(-\pi)cos(2x) = -sin(2x)[/tex]