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løse likning
Posted: 24/08-2016 19:52
by hhae
Hvordan løser likningen
2.5 (x--1.2)^5=9.0
Re: løse likning
Posted: 24/08-2016 20:24
by zell
[tex](x-1.2)^5 = \frac{9}{2.5} \ \Rightarrow \ x-1.2 = \sqrt[5]{\frac{9}{2.5}}[/tex]
Re: løse likning
Posted: 24/08-2016 20:31
by Dolandyret
hhae wrote:Hvordan løser likningen
2.5 (x--1.2)^5=9.0
Skal det være 1 eller 2 "minuser"?
[tex]2.5*(x-1.2)^5=9\\ 5ln(x-1.2)=ln (\frac9 {2.5})\\ ln (x-1.2)=0.256\\ x=e^{0.256}+1.2\\x=2.49[/tex]