difflikning
Posted: 10/03-2018 11:57
Hvordan løser jeg denne:
xy'+1=y
xy'+1=y
[tex]\int\frac{dy}{y-1}=\int\frac{dx}{x}\\ \\ \ln|y-1|=\ln|x|+d\\ y-1=c*e^x\\ y=c*e^x+1[/tex]polll wrote:Hvordan løser jeg denne:
xy'+1=y
[tex]\int\frac{dy}{y-1}=\int\frac{dx}{x}\\ \\ \ln|y-1|=\ln|x|+d\\ y-1=c*e^x\\ y=c*e^x+1[/tex]polll wrote:Hvordan løser jeg denne:
xy'+1=y