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Kvadratrot

Posted: 01/04-2006 10:54
by Trond
Hvordan regner jeg ut disse to?

Image

Fasitsvar:
37
-20

Posted: 01/04-2006 16:34
by Solar Plexsus
[tex](3\sqrt{3})^2 \:+\: 5\sqrt[4]{16} \;=\; (3 \cdot 3^{1/2})^2 \:+\: 5 \cdot (16)^{1/4} \;=\; (3^{3/2})^2 \:+\: 5 \cdot (2^4)^{1/4} \;=\; 3^3 \:+\: 5 \cdot 2^1 \;=\; 27 \:+\: 10 \;=\; 37[/tex].

[tex](\sqrt{2})^4 \:-\: (2 \cdot \sqrt[3]{3})^3 \;=\; (2^{1/2})^4 \:-\: (2 \cdot 3^{1/3})^3 \;=\; 2^2 \:-\: 2^3 \cdot 3^1 \;=\; 4 \:-\: 8 \cdot 3 \;=\; 4 \:-\: 24 \;=\; -20.[/tex]