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Logaritme
Posted: 02/04-2006 20:17
by Guest
2lgx + 3 = lgx +2
Noen som kan vise hvordan man løser denne?
Takk..
Posted: 02/04-2006 20:25
by Knut Erik
[tex]{ \begin{eqnarray} 2\lg x + 3 &=& \lg x + 2 \cr 2\lg x - \lg x &=& 2 - 3 \cr \lg x &=& - 1 \cr 10^{\lg x} &=& 10^{ - 1} \cr x &=& 0,1 \cr\end{eqnarray}}[/tex]
Posted: 02/04-2006 20:26
by Mayhassen
2lgx + 3 = lgx + 2
2lgx - lgx = 2 -3
lgx = -1
10^lgx = 10^-1
x = 0,1
Posted: 02/04-2006 20:30
by Guest
Takk skal dere ha!