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				Logaritme
				Posted: 02/04-2006 20:17
				by Guest
				2lgx + 3 = lgx +2 
Noen som kan vise hvordan man løser denne?
Takk..
			 
			
					
				
				Posted: 02/04-2006 20:25
				by Knut Erik
				[tex]{ \begin{eqnarray}  2\lg x + 3 &=& \lg x + 2 \cr   2\lg x - \lg x &=& 2 - 3 \cr   \lg x &=&  - 1 \cr   10^{\lg x}  &=& 10^{ - 1}  \cr   x &=& 0,1 \cr\end{eqnarray}}[/tex]
			 
			
					
				
				Posted: 02/04-2006 20:26
				by Mayhassen
				2lgx + 3 = lgx + 2
2lgx - lgx = 2 -3
lgx = -1
10^lgx = 10^-1
x = 0,1
			 
			
					
				
				Posted: 02/04-2006 20:30
				by Guest
				Takk skal dere ha!