Trigonometrisk ligning
Posted: 28/05-2006 22:22
sin x - sin 2x = 0, x [0, 360]
sin(2x)=2sin(x)cos(x)Anonymous wrote:sin x - sin 2x = 0, x [0, 360]
Får da:
sin(x)-2sin(x)cos(x)=sin(x)(1-2cos(x))=0
Da må enten sin(x)=0 eller 1-2cos(x)=0
sin(x)=0 =>x=0 , 180 eller 360
1-2cos(x)=0 =>cos(x)=1/2 => x= 60