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Integrer [symbol:integral] 4/(x^1/3)

[symbol:integral] 4/(x^1/3) dx = [symbol:integral] 4*x^-(1/3) dx = 6x[sup]2/3[/sup] + C

Hvor blir det 6x, og ikke 4x?

[symbol:integral] 4/(x^1/3) = 4 * [symbol:integral] x^-1/3

= 4 * 1/ (-1/3 + 1) *x^-1/3+1 + C = 4* (3/3)/(2/3) * x^2/3 + C

= 4* (3/2) * x^2/3 + C = (12/2) * x^2/3 + C = 6x^2/3

4 * 3/2 = 6