Potenser
Posted: 17/09-2006 14:44
Hvordan regner jeg ut dette?
3^(1/3) / (1/3)^(2/3) =
3^(1/3) / (1/3)^(2/3) =
Gitt:
(3[sup]1/3[/sup]) / (1/3)[sup]2/3[/sup]
= (3[sup]1/3[/sup]) / (3[sup](-1*2/3)[/sup])
= (3[sup]1/3[/sup]) / (3[sup]-2/3[/sup])
= (3[sup]1/3[/sup]) * (3[sup]2/3[/sup])
= 3[sup](1/3)+(2/3)[/sup]
= 3[sup]1[/sup]
= 3