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dervasjon
Posted: 01/11-2006 12:14
by janneamble
deriver
f (x) = ln ( √ x )
Re: dervasjon
Posted: 01/11-2006 14:20
by Janhaa
janneamble wrote:deriver
f (x) = ln ( √ x )
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u = [symbol:rot] (X)
[tex]{d\over dx}ln(u)\;=\;[/tex][tex]u `\over u[/tex]
[tex](ln\sqrt {x})`\;=\;[/tex][tex]0.5x^{-0.5}\over x^{0.5}[/tex]
[tex](ln\sqrt {x})`\;=\;[/tex][tex]0.5x^{-1}[/tex]
[tex](ln\sqrt {x})`\;=\;[/tex][tex]1\over {2}{x}[/tex]
Posted: 01/11-2006 15:52
by daofeishi
Du kan også benytte deg av at [tex] \ln (\sqrt{x}) = \frac{1}{2} \ln (x)[/tex]
[tex]\frac{d}{dx} \ \frac{1}{2} \ln (x) = \frac{1}{2x}[/tex]