matematikk.net

Slik er oppgaven:

(a [sup]-1[/sup] a [sup]3[/sup] [symbol:rot] a) [sup]4[/sup] / (a [sup]2[/sup]a [sup]-3[/sup] a [sup]1/4[/sup] ) [sup]8[/sup]

[tex](a^{-1}\cdot a^3 \cdot \sqrt{a})^4 = (a^2\cdot\sqrt{a})^4 = a^8\cdot a^2 = a^{10}[/tex]

[tex](a^2\cdot a^{-3}\cdot a^{1/4})^8 = {a^{-1}\cdot a^{1/4})^8 = a^{-8}\cdot a^2 = a^{-6}[/tex]


[tex]\frac {a^{10}}{a^{-6}} = a^{16}[/tex]