(2a+5b)^2=
(2x)- 5/4)^2=
(3-x)(3+x)=
kvadratsetningene?
Moderatorer: Aleks855, Gustav, Nebuchadnezzar, Janhaa, DennisChristensen, Emilga
-
Nebuchadnezzar
- Fibonacci
- Innlegg: 5648
- Registrert: 24/05-2009 14:16
- Sted: NTNU
[tex](a+b)^2 \, = \, a^2 \, + \, 2ab \, + b^2 [/tex]
[tex](a-b)^2 \, = \, a^2 \, - \, 2ab \, + \, a^2 [/tex]
[tex](a-b)(a+b) \, = \, a^2 \, - \, b^2 [/tex]
[tex](a-b)^2 \, = \, a^2 \, - \, 2ab \, + \, a^2 [/tex]
[tex](a-b)(a+b) \, = \, a^2 \, - \, b^2 [/tex]