1)
If xy = 7 and x - y = 5, then x²y - xy² =
A) 2
B) 12
C) 24
D) 35
E) 70
2)
"If |2-x| < 3, which of the following is a possible value of x ?"
A) 4
B) 5
C) 6
D) 7
E) 8
another unsolvable equation...
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Moonsailorkitten
- Pytagoras
- Posts: 7
- Joined: 01/08-2010 23:42
- Location: London
Ok... Disse 2 er uløselige.. to av "multiple-choise" matteoppgavene i SAT-boken min, og uheldigvis står det derfor ingen forklaring av fremgangsmåte. Help anyone? Kan noen gi forklaring og fremgangsmåte? x
1)
If xy = 7 and x - y = 5, then x²y - xy² =
A) 2
B) 12
C) 24
D) 35
E) 70
2)
"If |2-x| < 3, which of the following is a possible value of x ?"
A) 4
B) 5
C) 6
D) 7
E) 8
1)
If xy = 7 and x - y = 5, then x²y - xy² =
A) 2
B) 12
C) 24
D) 35
E) 70
2)
"If |2-x| < 3, which of the following is a possible value of x ?"
A) 4
B) 5
C) 6
D) 7
E) 8
