hvordan løse:
lg(10^2-1)-lg9
forenkle uttrykk ved hjelp av logaritmesetningene
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Hva legger du i å "løse" et tall?
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Dolandyret
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[tex]lg(10^2-1)-lg9=lg(99)-lg(9)=lg(\frac{99}9)=lg(11)\approx1.04[/tex]Vg2elev wrote:hvordan løse:
lg(10^2-1)-lg9
Last edited by Dolandyret on 09/09-2016 10:51, edited 1 time in total.
"I want to die peacefully in my sleep like my grandfather, not screaming in terror like his passengers."
$\approx$Dolandyret wrote:[tex]lg(11)=1.04[/tex]