Noen som kan hjelpe meg?
(/ betyr brøk)
2/5 X2 - 5/2 X(X-2)-3x
og
3a/4 + 1/4 b (b-a/b) + 1/2 b^2
Potenser
Moderators: Aleks855, Gustav, Nebuchadnezzar, Janhaa, DennisChristensen, Emilga
Hæ? Skal man forkorte eller noe sånt?
[tex]\frac{2}{5}X2 - \frac{5}{2} X(X-2) - 3x[/tex]
Mener du [tex]\frac{2}{5}x^2 - \frac{5}{2}x(x-2) - 3x[/tex] kanskje?
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[tex]\frac{3a}{4} + \frac{1}{4}b (b - \frac{a}{b}) + \frac{1}{2} b^2[/tex]
[tex]\frac{3a}{4} + \frac{1}{4}b^2 - \frac{a}{4b} + \frac{1}{2} b^2[/tex]
[tex]\frac{3ab}{4b} + \frac{b^3}{4b} - \frac{a}{4b} + \frac{2b^3}{4b}[/tex]
[tex]\frac{2b^3 + 3ab - a}{4b}[/tex]
[tex]\frac{2}{5}X2 - \frac{5}{2} X(X-2) - 3x[/tex]
Mener du [tex]\frac{2}{5}x^2 - \frac{5}{2}x(x-2) - 3x[/tex] kanskje?
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[tex]\frac{3a}{4} + \frac{1}{4}b (b - \frac{a}{b}) + \frac{1}{2} b^2[/tex]
[tex]\frac{3a}{4} + \frac{1}{4}b^2 - \frac{a}{4b} + \frac{1}{2} b^2[/tex]
[tex]\frac{3ab}{4b} + \frac{b^3}{4b} - \frac{a}{4b} + \frac{2b^3}{4b}[/tex]
[tex]\frac{2b^3 + 3ab - a}{4b}[/tex]
