hei hvordan gjør jeg:
[symbol:integral] xe^3x dx
merci
Delvis integrasjon
Moderators: Aleks855, Gustav, Nebuchadnezzar, Janhaa, DennisChristensen, Emilga
[tex]u = x \qquad u^\prime = 1[/tex]
[tex]v^\prime = e^{3x} \qquad v = \frac 13 e^{3x}[/tex]
[tex]\int x e^{3x} dx = x \cdot \frac 13 e^{3x} - \int 1 \cdot \frac 13 e^{3x} dx = \underline{\underline{\frac 13 x e^{3x} - \frac 19 e^{3x} +C}}[/tex]
[tex]v^\prime = e^{3x} \qquad v = \frac 13 e^{3x}[/tex]
[tex]\int x e^{3x} dx = x \cdot \frac 13 e^{3x} - \int 1 \cdot \frac 13 e^{3x} dx = \underline{\underline{\frac 13 x e^{3x} - \frac 19 e^{3x} +C}}[/tex]