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e^(2 ln [symbol:rot]a)
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Du har [tex]e^{2\ln(\sqr{a})}[/tex]
husk at [tex]t\cdot \ln(v)=\ln(v^t)[/tex]
Og at [tex]e^{\ln(v)}=v[/tex]
husk at [tex]t\cdot \ln(v)=\ln(v^t)[/tex]
Og at [tex]e^{\ln(v)}=v[/tex]
Last edited by Olorin on 11/08-2008 00:58, edited 1 time in total.
The square root of Chuck Norris is pain. Do not try to square Chuck Norris, the result is death.
http://www.youtube.com/watch?v=GzVSXEu0bqI - Tom Lehrer
http://www.youtube.com/watch?v=GzVSXEu0bqI - Tom Lehrer
Begge metodene er fine, og fører fram =) Så bruk den du synes er mest forståelig selv
The square root of Chuck Norris is pain. Do not try to square Chuck Norris, the result is death.
http://www.youtube.com/watch?v=GzVSXEu0bqI - Tom Lehrer
http://www.youtube.com/watch?v=GzVSXEu0bqI - Tom Lehrer
