kan noen hjelpe og derivere dette:
y(x) = (e^4x) * (4cosx + Bcosx)
Diff.likn. Derivasjon
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[tex](uv)^\prime=u^\prime v + uv^\prime[/tex]
[tex]u=e^{4x},\,\ u^\prime=4e^{4x}[/tex]
[tex]v=4\cos(x)+B\cos(x),\,\ v^\prime=-4\sin(x)-B\sin(x)=-(4+B)\sin(x)[/tex]
[tex]u=e^{4x},\,\ u^\prime=4e^{4x}[/tex]
[tex]v=4\cos(x)+B\cos(x),\,\ v^\prime=-4\sin(x)-B\sin(x)=-(4+B)\sin(x)[/tex]
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