[tex]f(y) = 3+6y[/tex]
[tex]f(y) = 3+6y = -2[/tex]
Dette gir:
[tex]6y = 1 \ \Rightarrow \ y = -\frac{5}{6}[/tex]
[tex]\sin{\pi x} = -\frac{5}{6}[/tex]
[tex]x = \frac{-0.985}{\pi} + 2n \ \vee \ x = 1 + \frac{0.985}{\pi} + 2n[/tex]
[tex]x = 1.68 \ \vee \ x = 1.31[/tex]
Her var den ene k tallet lik 1 og den andre lik 0, hva skiller tallene k mellom de to oppgavene?
