Jeg har klart alt frem til 6.51 e).
Her har jeg stilt opp proposjonen [tex]\frac{AC}{AD} = \frac{AE}{AC}[/tex]
eller [tex]AC^2 = AD \cdot AE[/tex].
Jeg skal sltså bevise at [tex]AC^2 + BC^2 = AB^2[/tex]
Men hva skal jeg gjøre nå?
Bevise a^2 + b^2 = c^2
Moderators: Aleks855, Gustav, Nebuchadnezzar, Janhaa, DennisChristensen, Emilga
(Beklager utydelig bilde. Hvis noe er uklart kan jeg skrive det opp.)
Jeg har klart alt frem til 6.51 e).
Her har jeg stilt opp proposjonen [tex]\frac{AC}{AD} = \frac{AE}{AC}[/tex]
eller [tex]AC^2 = AD \cdot AE[/tex].
Jeg skal sltså bevise at [tex]AC^2 + BC^2 = AB^2[/tex]
Men hva skal jeg gjøre nå?
Jeg har klart alt frem til 6.51 e).
Her har jeg stilt opp proposjonen [tex]\frac{AC}{AD} = \frac{AE}{AC}[/tex]
eller [tex]AC^2 = AD \cdot AE[/tex].
Jeg skal sltså bevise at [tex]AC^2 + BC^2 = AB^2[/tex]
Men hva skal jeg gjøre nå?
du har jo at [tex]\,\,AC^2\,=\,AE\cdot AD\,=\,b^2[/tex]
og fra tegninga blir AD = c - a og AE = c + a
slik at:
[tex]b^2\,=\,(c+a)(c-a)\,=\,c^2\,-\,a^2[/tex]
og fra tegninga blir AD = c - a og AE = c + a
slik at:
[tex]b^2\,=\,(c+a)(c-a)\,=\,c^2\,-\,a^2[/tex]
Last edited by Janhaa on 11/05-2008 14:25, edited 1 time in total.
La verken mennesker eller hendelser ta livsmotet fra deg.
Marie Curie, kjemiker og fysiker.
[tex]\large\dot \rho = -\frac{i}{\hbar}[H,\rho][/tex]
Marie Curie, kjemiker og fysiker.
[tex]\large\dot \rho = -\frac{i}{\hbar}[H,\rho][/tex]
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