Noen som kan ta denne?
lg(11-x) - lg(2-x) = 1
Logaritme
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Hei,-
log(11-x)-log(2-x)=1
log[(11-x)/(2-x)]=1 (log a - log b = log a/b)
(11-x)/(2-x)=10^1=10 (10^(log x)=x)
11-x=20-10x
9x=9
x=1
log(11-x)-log(2-x)=1
log[(11-x)/(2-x)]=1 (log a - log b = log a/b)
(11-x)/(2-x)=10^1=10 (10^(log x)=x)
11-x=20-10x
9x=9
x=1