Stress, sette 2 eksponentielle likninger opp mot hverandre og finne krysningspunktet... bare synd at jeg aldri har lært hvordan.
127 000 * 1,06^x = 280 000 * 0,87^x
Eksponential Likning
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[tex]127000*1.06^x=280000*0.87^x[/tex]
[tex] \frac{1.06^x}{0.87^x}=\frac{280000}{127000}[/tex]
[tex] (\frac{106}{87})^x=\frac{280}{127}[/tex]
[tex]\ln(\frac{106}{87})*x=\ln(\frac{280}{127})[/tex]
[tex]x=\frac{\ln(\frac{280}{127})}{\ln(\frac{106}{87})}\approx(4)[/tex]
[tex] \frac{1.06^x}{0.87^x}=\frac{280000}{127000}[/tex]
[tex] (\frac{106}{87})^x=\frac{280}{127}[/tex]
[tex]\ln(\frac{106}{87})*x=\ln(\frac{280}{127})[/tex]
[tex]x=\frac{\ln(\frac{280}{127})}{\ln(\frac{106}{87})}\approx(4)[/tex]
