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derivasjon
Posted: 02/06-2006 17:37
by Guest
Hvordan deriverer man denne:
g(x)=(x+cos x)^3
Posted: 02/06-2006 17:46
by Knut Erik
[tex]g(x) = (x + \cos x)^3 \cr g^,(u) = u^3 *u^, \cr g^,(u) = 3u^2 *u^, \cr g^,(x) = 3(x + \cos x)^2 * - \sin x \cr g^,(x) = - 3\sin x(x + \cos x)^2 \cr[/tex]
Re: derivasjon
Posted: 02/06-2006 17:50
by Guest
Anonymous wrote:Hvordan deriverer man denne:
g(x)=(x+cos x)^3
Kjerneregel, kjerneregel min venn.
[tex]g(x)=(x+cos(x))^3\\u^3\text{ hvor u=x+cos(x) }\\ \frac{du}{dx}=1-sin(x)\\\frac{d}{dx}g(x)=3(x+cos(x))^2(1-sin(x))[/tex]
Posted: 02/06-2006 18:39
by Guest
tusen takk!!!!!